Key Concept: Real-world Application, Reaction Equations
a) $\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$
[Solution Description]
The objective is to identify the balanced chemical reaction occurring when calcium hydroxide reacts with carbon dioxide in water to produce calcium carbonate and water. We begin by writing the unbalanced equation:
$\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$
To balance, ensure equal numbers of each type of atom on both sides:
Start with calcium (Ca):
– 1 Ca on both sides.
Next, balance the oxygen atoms:
– On the left: 2 from $\text{Ca(OH)}_2$ + 2 from $\text{CO}_2$ = 4 oxygens.
– On the right: 3 in $\text{CaCO}_3$ + 1 in $\text{H}_2\text{O}$ = 4 oxygens.
Finally, check hydrogen:
– 2 H on both sides from $\text{H}_2\text{O}$.
Therefore, the balanced equation is:
$\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$
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a) $\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$
[Solution Description]
The objective is to identify the balanced chemical reaction occurring when calcium hydroxide reacts with carbon dioxide in water to produce calcium carbonate and water. We begin by writing the unbalanced equation:
$\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$
To balance, ensure equal numbers of each type of atom on both sides:
Start with calcium (Ca):
– 1 Ca on both sides.
Next, balance the oxygen atoms:
– On the left: 2 from $\text{Ca(OH)}_2$ + 2 from $\text{CO}_2$ = 4 oxygens.
– On the right: 3 in $\text{CaCO}_3$ + 1 in $\text{H}_2\text{O}$ = 4 oxygens.
Finally, check hydrogen:
– 2 H on both sides from $\text{H}_2\text{O}$.
Therefore, the balanced equation is:
$\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}$